document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261830>Question 261830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 45-45-90 triangle has a hypotenuse of length 11. What is the length of one of its legs? If necessary, round your answer to two decimal places.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192997 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2s^2 = 11^2 = 121<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+sqrt%28121%2F2%29 ALIGN=MIDDLE  ALT=\"s+=+sqrt%28121%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+11sqrt%282%29%2F2 ALIGN=MIDDLE  ALT=\"s+=+11sqrt%282%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s =~ 7.78<BR>\n" );
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