document.write( "Question 261856: How much water must be added to 20.0 mL of a 60.0% slaine solution in order to make a 45.0% saline solution. Please help solve. Thank You! \n" ); document.write( "
Algebra.Com's Answer #192988 by Alan3354(69443)\"\" \"About 
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How much water must be added to 20.0 mL of a 60.0% slaine solution in order to make a 45.0% saline solution.
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\n" ); document.write( "0.6*20 = 12 ml of salt
\n" ); document.write( "For 12 ml to be 45%, the total is 12/0.45
\n" ); document.write( "= 80/3 ml total
\n" ); document.write( "Add 20/3 ml of water
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