document.write( "Question 261856: How much water must be added to 20.0 mL of a 60.0% slaine solution in order to make a 45.0% saline solution. Please help solve. Thank You! \n" ); document.write( "
Algebra.Com's Answer #192987 by checkley77(12844)\"\" \"About 
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.60*20=.45(20+X)
\n" ); document.write( "12=9+.45X
\n" ); document.write( ".45X=12-9
\n" ); document.write( ".45X=3
\n" ); document.write( "X=3/.45
\n" ); document.write( "X=6.667 ML OPF WATER IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".60*20=.45(20+6.667)
\n" ); document.write( "12=.45*26.667
\n" ); document.write( "12=12
\n" ); document.write( "
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