document.write( "Question 261856: How much water must be added to 20.0 mL of a 60.0% slaine solution in order to make a 45.0% saline solution. Please help solve. Thank You! \n" ); document.write( "
Algebra.Com's Answer #192987 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .60*20=.45(20+X) \n" ); document.write( "12=9+.45X \n" ); document.write( ".45X=12-9 \n" ); document.write( ".45X=3 \n" ); document.write( "X=3/.45 \n" ); document.write( "X=6.667 ML OPF WATER IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".60*20=.45(20+6.667) \n" ); document.write( "12=.45*26.667 \n" ); document.write( "12=12 \n" ); document.write( " |