document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261828>Question 261828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 3 hours. How much time would it take for them to mow the lawn together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192980 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6*3/(6+3)<BR>\n" );
document.write( "18/9=2 HOURS WHEN THEY WORK TOGETHER. </SPAN>\n" );
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