document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261855>Question 261855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One grade of oil has 0.50% of an additive and a higher grade has 0.75% of the additive. How many liters of each must be used to have 1000 L of a mixture with 0.65% of the aadditive? Please help solve. Thank You! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192972 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .75X+.50(1,000-X)=.65*1,000<BR>\n" );
document.write( ".75X+500-.50X=650<BR>\n" );
document.write( ".25X=650-500<BR>\n" );
document.write( ".25X=150<BR>\n" );
document.write( "X=150/.25<BR>\n" );
document.write( "X=600 AMOUNT OF 75% ADDITIVE IS USED.<BR>\n" );
document.write( "1,000-600=400 AMOUNT OF 50% ADDITIVE IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".75*600+.50*400=.65*1,000<BR>\n" );
document.write( "450+200=650<BR>\n" );
document.write( "650=650<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );