document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261878>Question 261878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the y=mx+b form of these systems \r<BR>\n" );
document.write( "\n" );
document.write( "x+y=4<BR>\n" );
document.write( "2x+y=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192959 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To write in the form y = mx + b, we need to solve for y.<BR>\n" );
document.write( "(i) x+y=4<BR>\n" );
document.write( "subtract x to get<BR>\n" );
document.write( " y = -x+4<BR>\n" );
document.write( "---<BR>\n" );
document.write( "(ii) 2x+y=6<BR>\n" );
document.write( "subtract 2x to get<BR>\n" );
document.write( "y = -2x + 6<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Both are now in y = mx+ b form<BR>\n" );
document.write( "--<BR>\n" );
document.write( "If you wanted the values of x and y that make them consistent, then we get<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "y = 2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );