document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261876>Question 261876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose M is between L and N use segment Additing postulate to solve for the variable then find lengths of line LM, line MN and line LN.\r<BR>\n" );
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document.write( "LM= 3x+8<BR>\n" );
document.write( "MN= 2x-5<BR>\n" );
document.write( "LN= 23  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192948 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "The segment addition principle says that if a segment is divided into a number of smaller segments then I can add the measures of all of the small segments to get the measure of the original segment.  In other words:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ LM\ +\ MN\ =\ LN\">\r<BR>\n" );
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document.write( "Substituting the given values we get:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(3x\,+\,8\right)\ +\ \left(2x\,-\,5\right)\ =\ 23\">\r<BR>\n" );
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document.write( "Solve the equation for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\">.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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