document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261860>Question 261860</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help solve: a karat equals 1/24 part of gold in an alloy. (for example 9 karat gold in 9/24 gold) How many grams of a 9 karat gold must be mixed with 18 karat gold to get 200 g of 14 karat gold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192936 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Let <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\"> represent the amount of 9 karat gold.  Then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \frac{9}{24}x\"> represents the amount of pure gold in the unknown amount of 9k gold.  Since the total amount must be 200 grams, then the amount of 18k gold must be <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 200\ -\ x\">, and the amount of pure gold in this amount is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \frac{18}{24}\left(200\ -\ x\right)\">.  The amount of pure gold in the 200 grams of 14k gold must be <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \frac{14}{24}\left(200\right)\">.  The sum of the two amounts of pure gold in the two quantities to be mixed must equal the amount of pure gold in the mixture, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{9}{24}x\ +\ \frac{18}{24}\left(200\ -\ x\right)\ =\ \frac{14}{24}\left(200\right)\">\r<BR>\n" );
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document.write( "Solve for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\"> to answer the question.  Hint:  First multiply both sides of the equation by 24.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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