document.write( "Question 261862: a quantity of 13% acid solution is being diluted with some 3% acid solution.The final solution must be 8% acid and contain 90mL. How much of each solution must be added to accomplish this? \n" ); document.write( "
Algebra.Com's Answer #192929 by ptaylor(2198)\"\" \"About 
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Let x=amount of 13% solution needed
\n" ); document.write( "Then 90-x=amount of 3% solution needed
\n" ); document.write( "Now we know that the pure acid in the 13% solution (0.13x) plus the amount of pure acid in the 3% solution (0.03(90-x)) has to equal the amount of pure acid in the final mixture (0.08*90). So our equation to solve is:
\n" ); document.write( "0.13x+0.03(90-x)=0.08*90 simplify
\n" ); document.write( "0.13x+2.7-0.03x=7.2 subtract 2.7 from each side
\n" ); document.write( "0.13x+2.7-2.7-0.03x=7.2-2.7 collect like terms
\n" ); document.write( "0.1x=4.5 divide each side by 0.1
\n" ); document.write( "x=45 ml-----amount of 13% solution needed
\n" ); document.write( "90-x=90-45=45 ml amount of 3% solution needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.13*45+0.03*45=0.08*90
\n" ); document.write( "5.85+1.35=7.2
\n" ); document.write( "7.2=7.2\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "
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