document.write( "Question 261549: The two digits in the numerator of a fraction are reversed in its denominator. If 1 is subtracted from both the numerator and the denominator, the value of the resulting fraction is 1/2. The fraction whose numerator is the difference and whose denominator is the sum of the units and tens digits equals 2/5. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #192913 by ankor@dixie-net.com(22740)\"\" \"About 
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Let x = the 10's digit of the numerator
\n" ); document.write( "Let y = the units digit
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\n" ); document.write( "The two digits in the numerator of a fraction are reversed in its denominator. If 1 is subtracted from both the numerator and the denominator, the value of the resulting fraction is 1/2.
\n" ); document.write( "\"%2810x%2By+-+1%29%2F%2810y%2Bx+-+1%29\" = \"1%2F2\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "2(10x+y-1) = 10y+x-1)
\n" ); document.write( ":
\n" ); document.write( "20x + 2y - 2 = 10y + x -1
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\n" ); document.write( "20x - x = 10y - 2y - 1 + 2
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\n" ); document.write( "19x = 8y + 1
\n" ); document.write( ":
\n" ); document.write( " The fraction whose numerator is the difference and whose denominator is the sum of the units and tens digits equals 2/5.
\n" ); document.write( "\"%28y-x%29%2F%28y%2Bx%29\" = \"2%2F5\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "5(y - x) = 2(y + x)
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\n" ); document.write( "5y - 5x = 2y + 2x
\n" ); document.write( "5y - 2y = 2x + 5x
\n" ); document.write( "3y = 7x
\n" ); document.write( "y = \"7%2F3\"x
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\n" ); document.write( "Find the original fraction.
\n" ); document.write( "Replace y in the 1st equation; 19x = 8y + 1, with \"7%2F3\"x
\n" ); document.write( "19x * 8(\"7%2F3\"x) + 1
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\n" ); document.write( "19x - \"56%2F3\"x + 1
\n" ); document.write( "mult by 3
\n" ); document.write( "3(19x) = 56x + 3(1)
\n" ); document.write( "57x - 56x = 3
\n" ); document.write( "x = 3, is the numerator 10's digit
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\n" ); document.write( "Find y:
\n" ); document.write( "y = 3(\"7%2F3\")
\n" ); document.write( "y = 7, is the numerator units digit
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\n" ); document.write( "The original fraction: \"37%2F73\"
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\n" ); document.write( "Check by subtracting 1 from the numerator and denominator
\n" ); document.write( "\"36%2F72\" = \"1%2F2\"\r
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