document.write( "Question 261635: A sum of $113,000 is split between two investments, one paying 6% and the other 9%. If the total yearly interest amounted to $8550, how much was invested at 9%? \n" ); document.write( "
Algebra.Com's Answer #192854 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .09X+.06(113,000-X)=8,550 \n" ); document.write( ".09X+6,780-.06X=8,550 \n" ); document.write( ".03X=8,550-6,780 \n" ); document.write( ".03X=1,770 \n" ); document.write( "X=1,770/.03 \n" ); document.write( "X=59,000 ANS. FOR THE AMOUNT INVESTED @ 9%. \n" ); document.write( "113,000-59,000=54,000 \n" ); document.write( ".09*59,000+.06*54,000=8,550 \n" ); document.write( "5,310+3,240=8,550 \n" ); document.write( "8,550=8,550 \n" ); document.write( " \n" ); document.write( " |