document.write( "Question 261635: A sum of $113,000 is split between two investments, one paying 6% and the other 9%. If the total yearly interest amounted to $8550, how much was invested at 9%? \n" ); document.write( "
Algebra.Com's Answer #192854 by checkley77(12844)\"\" \"About 
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.09X+.06(113,000-X)=8,550
\n" ); document.write( ".09X+6,780-.06X=8,550
\n" ); document.write( ".03X=8,550-6,780
\n" ); document.write( ".03X=1,770
\n" ); document.write( "X=1,770/.03
\n" ); document.write( "X=59,000 ANS. FOR THE AMOUNT INVESTED @ 9%.
\n" ); document.write( "113,000-59,000=54,000
\n" ); document.write( ".09*59,000+.06*54,000=8,550
\n" ); document.write( "5,310+3,240=8,550
\n" ); document.write( "8,550=8,550
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