document.write( "Question 261742: 12+20ln(x)=90 \n" ); document.write( "
Algebra.Com's Answer #192853 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"+12%2B20ln%28x%29=90\"
\n" ); document.write( "\"20ln%28x%29=78\"
\n" ); document.write( "\"ln%28x%29=78%2F20=3.9\"
\n" ); document.write( "\"x=e%5E%283.9%29\" or approximately
\n" ); document.write( "\"x=49.4\"
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