document.write( "Question 261709: The perimeter of a rectangle is 48cm. The length is 12 cm longer than the width. Find the dimension \n" ); document.write( "
Algebra.Com's Answer #192833 by checkley77(12844)\"\" \"About 
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L=W+12
\n" ); document.write( "2L+2W=48
\n" ); document.write( "2(W+12)+2W=48
\n" ); document.write( "2W+24+2W=48
\n" ); document.write( "4W=48-24
\n" ); document.write( "4W=24
\n" ); document.write( "W=24/4
\n" ); document.write( "W=6 ANS. FOR THE WIDTH.
\n" ); document.write( "L=6+12=18 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*18+2*6=48
\n" ); document.write( "36+12=48
\n" ); document.write( "48=48
\n" ); document.write( "
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