document.write( "Question 261709: The perimeter of a rectangle is 48cm. The length is 12 cm longer than the width. Find the dimension \n" ); document.write( "
Algebra.Com's Answer #192833 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+12 \n" ); document.write( "2L+2W=48 \n" ); document.write( "2(W+12)+2W=48 \n" ); document.write( "2W+24+2W=48 \n" ); document.write( "4W=48-24 \n" ); document.write( "4W=24 \n" ); document.write( "W=24/4 \n" ); document.write( "W=6 ANS. FOR THE WIDTH. \n" ); document.write( "L=6+12=18 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*18+2*6=48 \n" ); document.write( "36+12=48 \n" ); document.write( "48=48 \n" ); document.write( " \n" ); document.write( " |