document.write( "Question 261710: Chuck and Dana agree to meet in Chicago for the weekend. Chcuk travels 114 miles in the same time that Dana travels 96 miles. If Chuck's rate of travel is 6 mph more than Dana's, then at what rate does Chuck travel? \n" ); document.write( "
Algebra.Com's Answer #192831 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "114=(R+6)T
\n" ); document.write( "T=114/(R+6) FOR CHUCK'S TRIP.
\n" ); document.write( "96=RT
\n" ); document.write( "T=96/R FOR DANA'S TRIP.
\n" ); document.write( "SEEING AS THE TIMES ARE THE SAME SET THESE 2 EQUATIONS EQUAL.
\n" ); document.write( "114/(R+6)=96/R CROSS MULTIPLY
\n" ); document.write( "96(R+6)=114R
\n" ); document.write( "96R+576=114R
\n" ); document.write( "96R-114R=-576
\n" ); document.write( "-18R=-576
\n" ); document.write( "R=-576/-18
\n" ); document.write( "R=32 MPH. IS DANA'S SPEED.
\n" ); document.write( "32+6=38 MPH. IS CHUCK'S SPEED.
\n" ); document.write( "PROOF:
\n" ); document.write( "114/38=96/32
\n" ); document.write( "3=3\r
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