document.write( "Question 261710: Chuck and Dana agree to meet in Chicago for the weekend. Chcuk travels 114 miles in the same time that Dana travels 96 miles. If Chuck's rate of travel is 6 mph more than Dana's, then at what rate does Chuck travel? \n" ); document.write( "
Algebra.Com's Answer #192831 by checkley77(12844) ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "114=(R+6)T \n" ); document.write( "T=114/(R+6) FOR CHUCK'S TRIP. \n" ); document.write( "96=RT \n" ); document.write( "T=96/R FOR DANA'S TRIP. \n" ); document.write( "SEEING AS THE TIMES ARE THE SAME SET THESE 2 EQUATIONS EQUAL. \n" ); document.write( "114/(R+6)=96/R CROSS MULTIPLY \n" ); document.write( "96(R+6)=114R \n" ); document.write( "96R+576=114R \n" ); document.write( "96R-114R=-576 \n" ); document.write( "-18R=-576 \n" ); document.write( "R=-576/-18 \n" ); document.write( "R=32 MPH. IS DANA'S SPEED. \n" ); document.write( "32+6=38 MPH. IS CHUCK'S SPEED. \n" ); document.write( "PROOF: \n" ); document.write( "114/38=96/32 \n" ); document.write( "3=3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |