document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261684>Question 261684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hour hand of a clock moves from 12 to 5 o’clock. Through how many degrees does it move? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192801 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12 to 6 would be 6 hours and 180 degrees.<BR>\n" );
document.write( "Set up a ratio.<BR>\n" );
document.write( "12 to 5 would be 5 hours. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F5=180%2FX ALIGN=MIDDLE  ALT=\"6%2F5=180%2FX\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X=180%2A%285%2F6%29 ALIGN=MIDDLE  ALT=\"X=180%2A%285%2F6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X=150 ALIGN=MIDDLE  ALT=\"X=150\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "X=150 degrees<BR>\n" );
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