document.write( "Question 261666: if a circular table is to be made that will have a top covered with material that costs $3.50 per square foot. The covering is to cost no more than $60. What is the maximum radius for the top of the table? \n" ); document.write( "
Algebra.Com's Answer #192792 by CharlesG2(834)\"\" \"About 
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if a circular table is to be made that will have a top covered with material that costs $3.50 per square foot. The covering is to cost no more than $60. What is the maximum radius for the top of the table?\r
\n" ); document.write( "\n" ); document.write( "$60/($3.50/square foot) = $60 * square foot/$3.50
\n" ); document.write( "60/3.50 = 6000/350 = 600/35 = 120/7 = 17.142857 square feet approximately maximum for square feet allowed and maximum area of the circular table allowed\r
\n" ); document.write( "\n" ); document.write( "pi * r^2 = area of circular table = 17.142857
\n" ); document.write( "r^2 = 5.456741 approximately
\n" ); document.write( "r = 2.335967 feet approximately maximum radius
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