document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261636>Question 261636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i find the produxt or quotient of 2k+8 over 6 divided by 3k+12 over 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192757 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's write this out to look like:<BR>\n" );
document.write( "2k+8/6 divided by 3k+12/2 This will be rewritten as:<BR>\n" );
document.write( "2k+8/6 times 2/3k+12 This can be further rewritten as:<BR>\n" );
document.write( "2(k+4)/6  times 2/3(k+4)  Notice that (K+4) cancels out and 6 and 2 reduce to 1/3.<BR>\n" );
document.write( "2/3 times 1/3 So the answer turns out to be:<BR>\n" );
document.write( "2/9<BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
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document.write( "www.math-unlock.com  </SPAN>\n" );
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