document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261636>Question 261636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i find the produxt or quotient of 2k+8 over 6 divided by 3k+12 over 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192755 by </B><A HREF=/tutors/aboutme.mpl?userid=butterfliiizzz><B>butterfliiizzz(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=butterfliiizzz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=butterfliiizzz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In this problem, instead of dividing, you would multiply the reciprocal. The reciprocal just means an inverted or upside down fraction. <BR>\n" );
document.write( "So you can change 2k + 8/6 divided by 3k + 12/2 to:<BR>\n" );
document.write( "2k + 8/6 times2/3k +12.  So to multiply the tops (numerators), you would have to use the distributive property to come up with 2* 2k =4k & 2*8 =16<BR>\n" );
document.write( "So the numerator would be 4k + 16.<BR>\n" );
document.write( "Then we multiply out the denominators using the distributive property: <BR>\n" );
document.write( "6* 3k =18k  & 6*12 = 72  <BR>\n" );
document.write( "So the denominator would be 18k + 72.<BR>\n" );
document.write( "You end up with 4k + 16/18k +72.<BR>\n" );
document.write( "This can be reduced to 2k +2/9k +9 </SPAN>\n" );
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