document.write( "Question 261624: barbie, judy, and sulty all have birthdays in the same day. barbie's present age is two years less than the sum of judy and sulty's age. in 5 years, barbie will be twice as old as judy will be then. two years ago, judy was half as old as sulty was. how old is each now? \n" ); document.write( "
Algebra.Com's Answer #192752 by mananth(16946)\"\" \"About 
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Let their ages be as follows.
\n" ); document.write( "Barbie =x
\n" ); document.write( "Judy=y
\n" ); document.write( "Sulty=z\r
\n" ); document.write( "\n" ); document.write( "X=(y+z—2)
\n" ); document.write( "X+5=2(y+5)
\n" ); document.write( "y-2=1/2*(z-2)\r
\n" ); document.write( "\n" ); document.write( "Simplify all the equations\r
\n" ); document.write( "\n" ); document.write( "x-y-z=-2 ----1
\n" ); document.write( "x-2y=5 ------2
\n" ); document.write( "2y-z=2-------3\r
\n" ); document.write( "\n" ); document.write( "Solve eq 2 &3 Add 2&3\r
\n" ); document.write( "\n" ); document.write( "We get x-z=7\r
\n" ); document.write( "\n" ); document.write( "X=z+7\r
\n" ); document.write( "\n" ); document.write( "Substitute the value of x in equation 1\r
\n" ); document.write( "\n" ); document.write( "z+7 –y-z=-2
\n" ); document.write( "y=9\r
\n" ); document.write( "\n" ); document.write( "x-2*y= =5 -----2
\n" ); document.write( "x-18=5
\n" ); document.write( "x=23\r
\n" ); document.write( "\n" ); document.write( "z=16\r
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