document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261618>Question 261618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y=2x-6<BR>\n" );
document.write( "y=5x+15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192750 by </B><A HREF=/tutors/aboutme.mpl?userid=butterfliiizzz><B>butterfliiizzz(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=butterfliiizzz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=butterfliiizzz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For this problem, it is telling you the value of y.  So simply plug that in where the y is and then solve for x.\r<BR>\n" );
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document.write( "2x - 6 = 5x + 15  So what I would do is subtract 5x from each side to get:<BR>\n" );
document.write( "-3x - 6 = 15  Now we can add six to both sides, to get rid of the negative 6.<BR>\n" );
document.write( "-3x = 21  Now, to get x by itself, we need to divide each side by -3.  \r<BR>\n" );
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document.write( "-3/-3 =1  We want 1x (or simply, x) on the left.   On the right, 21/-3 = -7\r<BR>\n" );
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document.write( "So x = -7 </SPAN>\n" );
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