document.write( "Question 261632: The perimeter of a rectangle is 100 meters. Its length is 7 meters less than twice its width. Find its area. \n" ); document.write( "
Algebra.Com's Answer #192748 by mananth(16946)\"\" \"About 
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The perimeter of a rectangle is 100 meters. Its length is 7 meters less than twice its width. Find its area\r
\n" ); document.write( "\n" ); document.write( "Let the width be x
\n" ); document.write( "Twice width = 2x
\n" ); document.write( "Seven less than twice the width = 2x-7\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2*(l+w)
\n" ); document.write( " = 2*(2x-7+x)
\n" ); document.write( " = 2*(3x-7)
\n" ); document.write( " = 6x-14 =100
\n" ); document.write( "2x= 114
\n" ); document.write( "X= 57
\n" ); document.write( "Width =2x = 114\r
\n" ); document.write( "\n" ); document.write( "Area = L*w= 114 * 57=6498 square meters\r
\n" ); document.write( "\n" ); document.write( "M Ananth------------ mananth@hotmail.com\r
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