document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261619>Question 261619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I was hoping you could help me with a question. \"One train leaves city A heading for city B which is 390 miles away. At the same time a second train leaves city B heading for city A, Going 15 mph faster then the first train. If they meet in 3 hours and 20 minutes how fast were the trains traveling? <BR>\n" );
document.write( "I keep trying to put it in the formula 3.2(x)+ 3.2(x-15)=390 from there I get (simplified) 6.4x= 438\r<BR>\n" );
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document.write( "Please tell me where i'm going wrong<BR>\n" );
document.write( "Thank you so much.<BR>\n" );
document.write( "Vincent </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192741 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"One train leaves city A heading for city B which is 390 miles away. At the same time a second train leaves city B heading for city A, Going 15 mph faster then the first train. If they meet in 3 hours and 20 minutes how fast were the trains traveling?<BR>\n" );
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document.write( "Train A DATA:<BR>\n" );
document.write( "rate = x mph ; time = 3 1/3 = 10/3 hrs ; distance = rt = (10/3)x miles<BR>\n" );
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document.write( "Train B DATA:<BR>\n" );
document.write( "rate = x+15 mph ; time = (10/3) hrs ; distance = rt = (10/3)(x+15) miles<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "A distance + B distance = 390 miles<BR>\n" );
document.write( "(10/3)x + (10/3)(x+15) = 390<BR>\n" );
document.write( "10x + 10(x+15) = 1170<BR>\n" );
document.write( "20x + 150 = 1170<BR>\n" );
document.write( "20x = 1020<BR>\n" );
document.write( "x = 51 mph (Train A rate)<BR>\n" );
document.write( "x+15 = 66 mph (Train B rate)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( "I keep trying to put it in the formula 3.2(x)+ 3.2(x-15)=390 from there I get (simplified) 6.4x= 438 <BR>\n" );
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