document.write( "Question 32861: The lenghth of a rectanguler room is 5 feet more than 3 times the width.Find the dimensions if the perimeter is 62 feet? \n" ); document.write( "
Algebra.Com's Answer #19274 by sarah_adam(201)\"\" \"About 
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Let the length of the rectangular room be denoted as L ft
\n" ); document.write( "Let the width(breadth) of the rectangular room be denoted as B ft
\n" ); document.write( "Given Length of the room is 5 ft more than 3 times the Width
\n" ); document.write( "SO L = 5+3B
\n" ); document.write( "Also Given Perimeter P = 62 ft\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is the distance around the outside of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "So the perimeter of the rectangle is 2(L+B)\r
\n" ); document.write( "\n" ); document.write( "2(L+B) = 62
\n" ); document.write( "2(5+3B+B) = 62 (replacing the value of L)
\n" ); document.write( "2(5+4B) = 62
\n" ); document.write( "5+4B = 62/2
\n" ); document.write( "5+4B = 31
\n" ); document.write( "4B = 31 - 5 = 26
\n" ); document.write( "B = 26/4 = 6.5 ft
\n" ); document.write( "L = 5 + 3(6.5)
\n" ); document.write( "L = 24.5 ft\r
\n" ); document.write( "\n" ); document.write( "So the dimensions of the room are L = 24.5 ft and Width of the room is 6.5 ft
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