document.write( "Question 32861: The lenghth of a rectanguler room is 5 feet more than 3 times the width.Find the dimensions if the perimeter is 62 feet? \n" ); document.write( "
Algebra.Com's Answer #19274 by sarah_adam(201)![]() ![]() ![]() You can put this solution on YOUR website! Let the length of the rectangular room be denoted as L ft \n" ); document.write( "Let the width(breadth) of the rectangular room be denoted as B ft \n" ); document.write( "Given Length of the room is 5 ft more than 3 times the Width \n" ); document.write( "SO L = 5+3B \n" ); document.write( "Also Given Perimeter P = 62 ft\r \n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is the distance around the outside of the rectangle.\r \n" ); document.write( "\n" ); document.write( "So the perimeter of the rectangle is 2(L+B)\r \n" ); document.write( "\n" ); document.write( "2(L+B) = 62 \n" ); document.write( "2(5+3B+B) = 62 (replacing the value of L) \n" ); document.write( "2(5+4B) = 62 \n" ); document.write( "5+4B = 62/2 \n" ); document.write( "5+4B = 31 \n" ); document.write( "4B = 31 - 5 = 26 \n" ); document.write( "B = 26/4 = 6.5 ft \n" ); document.write( "L = 5 + 3(6.5) \n" ); document.write( "L = 24.5 ft\r \n" ); document.write( "\n" ); document.write( "So the dimensions of the room are L = 24.5 ft and Width of the room is 6.5 ft \n" ); document.write( " |