document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261547>Question 261547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please show me how to do this problem?\r<BR>\n" );
document.write( "\n" );
document.write( "-4<6-2x<4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192697 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's one way:<BR>\n" );
document.write( "-4<6-2x<4<BR>\n" );
document.write( "Rewrite the problem as a compound inequality:<BR>\n" );
document.write( "-4 < 6-2x and 6-2x < 4<BR>\n" );
document.write( "Add -6 to both sides of both inequalities:<BR>\n" );
document.write( "-10 < -2x and -2x < -2<BR>\n" );
document.write( "Divide both sides by -2 (remembering the special rule to reverse the inequality whenever multiplying or dividing both sides of it by any negative number):<BR>\n" );
document.write( "5 > x and x > 1<BR>\n" );
document.write( "This should be an acceptable solution. But you could rewrite this in the same format as the original problem:<BR>\n" );
document.write( "5 > x > 1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );