document.write( "Question 261542: Please help me solve this equation: log(base 3)100= -2\r
\n" ); document.write( "\n" ); document.write( "I tried to do -2(root)100, but I'm not sure if I did it right.
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Algebra.Com's Answer #192694 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
here is the original problem:
\n" ); document.write( "\"log%283%2C100%29=+-2\"
\n" ); document.write( "the challenge I have here is that there is no variable. If we rewrote as exponents, we would get
\n" ); document.write( "\"3%5E%28-2%29+=+100\"
\n" ); document.write( "which is not true.
\n" ); document.write( "If however, the 3 were a b, then we would have the following:
\n" ); document.write( "\"log%28b%2C100%29=+-2\"
\n" ); document.write( "and now using exponents, we get
\n" ); document.write( "\"b%5E%28-2%29+=+100\"
\n" ); document.write( "rewrite the 100 as a power, we get
\n" ); document.write( " \"b%5E%28-2%29+=+10%5E2\"
\n" ); document.write( "so,
\n" ); document.write( "\"b+=+1%2F10%29\"
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