document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261472>Question 261472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 5 percent salt solution is mixed with a 10% salt solution. How many mililiters of each solution are needed to obtain 400 mililiters of an 8% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192680 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 5 percent salt solution is mixed with a 10% salt solution. How many mililiters of each solution are needed to obtain 400 mililiters of an 8% solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "salt + salt = salt<BR>\n" );
document.write( "0.05x + 0.10(400-x) = 0.08*400<BR>\n" );
document.write( "Multiply thru by 100<BR>\n" );
document.write( "5x + 10*400 - 10x = 8*400<BR>\n" );
document.write( "-5x = -2*400<BR>\n" );
document.write( "x = 2*80<BR>\n" );
document.write( "x = 160 milimeters (amt. of 5% solution needed for the mixture)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "400-160 = 340 milimeter (amt of 10% solution needed for the mixture)<BR>\n" );
document.write( "=====================================================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );