document.write( "Question 247433: I am currently working on the question (8x)^(-1/2) = 1/4. The answer that I keep getting is that it is 4/3. This is an example of what I have been doing.
\n" ); document.write( "2^(3x(-1/2)) = 4^(-1)
\n" ); document.write( "2^(-3x/2) = 2^(-2).
\n" ); document.write( "-3x/2 = -4
\n" ); document.write( "x = 4/3\r
\n" ); document.write( "\n" ); document.write( "Could you please let me know where I am going wrong? The answer says that it is 2, but I'd really like to know how I'm going wrong. Thank you for your time, \r
\n" ); document.write( "\n" ); document.write( "Robyn
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Algebra.Com's Answer #192678 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
(8x)^(-1/2) = 1/4. The answer that I keep getting is that it is 4/3. This is an example of what I have been doing.
\n" ); document.write( "2^(3x(-1/2)) = 4^(-1) ** 2^3*x^(-1/2) ..... You included the x
\n" ); document.write( "2^(-3x/2) = 2^(-2).
\n" ); document.write( "-3x/2 = -4 **** The exponents are equal, so -3x/2 = -2
\n" ); document.write( "x = 4/3
\n" ); document.write( "------------
\n" ); document.write( "Do it like this:
\n" ); document.write( "(8x)^(-1/2) = 1/4
\n" ); document.write( "Multiply thru by (8x)^1/2
\n" ); document.write( "1 = sqrt(8x)/4
\n" ); document.write( "sqrt(8x) = 4
\n" ); document.write( "Square both sides
\n" ); document.write( "8x = 16
\n" ); document.write( "x = 2
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