document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32845>Question 32845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HELP!!  I am struggling in solving this equation. I am never sure on the negative numbers on how to figure.\r<BR>\n" );
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document.write( "Solve the following equation by first solving for y: 2x - 3y = 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19264 by </B><A HREF=/tutors/aboutme.mpl?userid=oo70mar><B>oo70mar(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oo70mar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> My advice is to first add 3y to both sides, so you won't have to worry about the coefficient of y being negative.  This will leave you with 2x = 12 + 3y.<BR>\n" );
document.write( "Then, subtract 12 from both sides.  You will have 2x - 12 = 3y.<BR>\n" );
document.write( "Finally, divide both sides by the coefficient of y, which is 3.\r<BR>\n" );
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document.write( "You will end up with (2/3)x-(12/3) = y, or\r<BR>\n" );
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document.write( "y = (2/3)x - 4.\r<BR>\n" );
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