document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261437>Question 261437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this equation Joe is 5 years older than Sally. In 15 years Joe will be 3 times as old as Sally is now. How old is Sally now? Hint: Write Joe's age now in terms of Sally's age now. Then write Joe's age in 15 years using the expression you just wrote for Joe's age now. Then using S for Sally's age now, write the equation in only one variable \"S\" and solve it. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192618 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the age of Sally = x<BR>\n" );
document.write( "Then the age of Joe  = x+5<BR>\n" );
document.write( "Also, in 15 years Joe will be 3 times as old as Sally is now.<BR>\n" );
document.write( "    x+5+15 = 3x<BR>\n" );
document.write( "    x+20 = 3x<BR>\n" );
document.write( "    20 = 3x-x<BR>\n" );
document.write( "    20 = 2x<BR>\n" );
document.write( "    2x = 20<BR>\n" );
document.write( "    x = 20/2<BR>\n" );
document.write( "    x = 10 years     </SPAN>\n" );
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