document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261349>Question 261349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 times as long as it is wide. If the length is decreased by 10 inches and the width is increased by 2 inches the perimeter will be 80 inches. Find the dimensions of the original field.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192606 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192606\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=4W<BR>\n" );
document.write( "2L+2W=P<BR>\n" );
document.write( "2(L-10)+2(W+2)=80<BR>\n" );
document.write( "2(4W-10)+2W+4=80<BR>\n" );
document.write( "8W-20+2W+4=80<BR>\n" );
document.write( "10W=80+20-4<BR>\n" );
document.write( "10W=96<BR>\n" );
document.write( "W=96/10<BR>\n" );
document.write( "W=9.6 ANS.<BR>\n" );
document.write( "2(L-10)+2(9.6+2)=80<BR>\n" );
document.write( "2L-20+2*11.6=80<BR>\n" );
document.write( "2L-20+23.2=80<BR>\n" );
document.write( "2L=80+20-23.2<BR>\n" );
document.write( "2L=76.8<BR>\n" );
document.write( "L=76.8/2<BR>\n" );
document.write( "L=38.4 ANS.<BR>\n" );
document.write( "2*38.4+2*9.6<BR>\n" );
document.write( "76.8+19.2=96 ANS. FOR THE ORIGINAL RECTANGLE. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );