document.write( "Question 261361: logbase3 12+ logbase3 x = 3 \n" ); document.write( "
Algebra.Com's Answer #192547 by Alan3354(69443)\"\" \"About 
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logbase3 12+ logbase3 x = 3
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\n" ); document.write( "\"log%283%2C12%29+%2B+log%283%2Cx%29+=+3\"
\n" ); document.write( "\"log%283%2C12x%29+=+3\"
\n" ); document.write( "\"12x+=+3%5E3\"
\n" ); document.write( "12x = 27
\n" ); document.write( "x = 9/4
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