document.write( "Question 261326: the voltage VL across an inductor L in an electrical circuit falls exponentially over time t. The relationship is VL = Vmax e^-t/T, Where T= L/R.
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document.write( "If L= 4.5H and R = 270 calculate T?
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document.write( "Vmax=10.4 volts
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document.write( "Calculate V for values of t from o to 0.5 seconds at intervals of 0.01? \n" );
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Algebra.Com's Answer #192532 by Theo(13342)![]() ![]() You can put this solution on YOUR website! formula is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "T = L/R \n" ); document.write( "L = inductance = 4.5 \n" ); document.write( "R = resistance 270 \n" ); document.write( "T = L/R = (4.5/270) = .016666666... \n" ); document.write( "t = time \n" ); document.write( "V[max] = 10.4 volts.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Calculate VL for values of t from 0 to .5 seconds at intervals of 0.01\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When t = 0, the formula of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When t = .1, the formula of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When t = .4, the formula of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "t v[max] T VL = V[max] * e^(-(t/T))\r\n" ); document.write( "0 10.4 0.016666667 10.4\r\n" ); document.write( "0.01 10.4 0.016666667 5.707641015\r\n" ); document.write( "0.02 10.4 0.016666667 3.132419804\r\n" ); document.write( "0.03 10.4 0.016666667 1.719108438\r\n" ); document.write( "0.04 10.4 0.016666667 0.943466714\r\n" ); document.write( "0.05 10.4 0.016666667 0.517785511\r\n" ); document.write( "0.06 10.4 0.016666667 0.284166713\r\n" ); document.write( "0.07 10.4 0.016666667 0.155953999\r\n" ); document.write( "0.08 10.4 0.016666667 0.085589369\r\n" ); document.write( "0.09 10.4 0.016666667 0.046972442\r\n" ); document.write( "0.1 10.4 0.016666667 0.025779023\r\n" ); document.write( "0.11 10.4 0.016666667 0.014147828\r\n" ); document.write( "0.12 10.4 0.016666667 0.007764492\r\n" ); document.write( "0.13 10.4 0.016666667 0.004261244\r\n" ); document.write( "0.14 10.4 0.016666667 0.00233862\r\n" ); document.write( "0.15 10.4 0.016666667 0.001283462\r\n" ); document.write( "0.16 10.4 0.016666667 0.000704379\r\n" ); document.write( "0.17 10.4 0.016666667 0.000386571\r\n" ); document.write( "0.18 10.4 0.016666667 0.000212155\r\n" ); document.write( "0.19 10.4 0.016666667 0.000116433\r\n" ); document.write( "0.2 10.4 0.016666667 6.38998E-05\r\n" ); document.write( "0.21 10.4 0.016666667 3.5069E-05\r\n" ); document.write( "0.22 10.4 0.016666667 1.92463E-05\r\n" ); document.write( "0.23 10.4 0.016666667 1.05626E-05\r\n" ); document.write( "0.24 10.4 0.016666667 5.79686E-06\r\n" ); document.write( "0.25 10.4 0.016666667 3.18138E-06\r\n" ); document.write( "0.26 10.4 0.016666667 1.74598E-06\r\n" ); document.write( "0.27 10.4 0.016666667 9.58214E-07\r\n" ); document.write( "0.28 10.4 0.016666667 5.25879E-07\r\n" ); document.write( "0.29 10.4 0.016666667 2.88609E-07\r\n" ); document.write( "0.3 10.4 0.016666667 1.58392E-07\r\n" ); document.write( "0.31 10.4 0.016666667 8.69273E-08\r\n" ); document.write( "0.32 10.4 0.016666667 4.77067E-08\r\n" ); document.write( "0.33 10.4 0.016666667 2.6182E-08\r\n" ); document.write( "0.34 10.4 0.016666667 1.4369E-08\r\n" ); document.write( "0.35 10.4 0.016666667 7.88586E-09\r\n" ); document.write( "0.36 10.4 0.016666667 4.32785E-09\r\n" ); document.write( "0.37 10.4 0.016666667 2.37518E-09\r\n" ); document.write( "0.38 10.4 0.016666667 1.30352E-09\r\n" ); document.write( "0.39 10.4 0.016666667 7.15389E-10\r\n" ); document.write( "0.4 10.4 0.016666667 3.92614E-10\r\n" ); document.write( "0.41 10.4 0.016666667 2.15471E-10\r\n" ); document.write( "0.42 10.4 0.016666667 1.18253E-10\r\n" ); document.write( "0.43 10.4 0.016666667 6.48987E-11\r\n" ); document.write( "0.44 10.4 0.016666667 3.56171E-11\r\n" ); document.write( "0.45 10.4 0.016666667 1.95471E-11\r\n" ); document.write( "0.46 10.4 0.016666667 1.07277E-11\r\n" ); document.write( "0.47 10.4 0.016666667 5.88747E-12\r\n" ); document.write( "0.48 10.4 0.016666667 3.23111E-12\r\n" ); document.write( "0.49 10.4 0.016666667 1.77327E-12\r\n" ); document.write( "0.5 10.4 0.016666667 9.73193E-13\r\n" ); document.write( " \n" ); document.write( "the graph of your equation looks like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the following graph shows the smaller values a little better since the y values are taken up to 1 max only.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "didn't matter too much as the drop off is very steep and the numbers after t = .2 are extremely small.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |