document.write( "Question 32814: 6'4\" and 8'1\"\r
\n" ); document.write( "\n" ); document.write( "how do i express the length in feet using mixed fractions AND improper fractions?? \n" ); document.write( "

Algebra.Com's Answer #19253 by sarah_adam(201) $\"\"$ $\"About$

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lets see the conversion of inch to ft\r
\n" ); document.write( "\n" ); document.write( "we know 1 ft = 12 inches
\n" ); document.write( "therfore 1 inch = 1/12 ft\r
\n" ); document.write( "\n" ); document.write( "6'4\" implies 6 ft 4 inches
\n" ); document.write( "as 1 inch = 1/12 ft therfore 4 inch = 4/12 ft that is 1/3 ft
\n" ); document.write( "therfore 6'4\" as a mixed fraction in terms of ft would be 6 1/3 ft
\n" ); document.write( "the same which in improper fraction would be 19/2 ft\r
\n" ); document.write( "\n" ); document.write( "for 6'4\"
\n" ); document.write( "mixed fraction : 6 1/3 ft
\n" ); document.write( "improper fraction : 19/3 ft (6*3 + 1)/3\r
\n" ); document.write( "\n" ); document.write( "8'1\" implies 8 ft 1inches
\n" ); document.write( "as 1 inch = 1/12 ft
\n" ); document.write( "therfore 8'1\" as a mixed fraction in terms of ft would be 8 1/12 ft
\n" ); document.write( "the same which in improper fraction would be 97/12 ft \r
\n" ); document.write( "\n" ); document.write( "for 8'1\"
\n" ); document.write( "mixed fraction : 8 1/12 ft
\n" ); document.write( "improper fraction : 97/12 ft (6*3 + 1)/3\r
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