document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261336>Question 261336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x = 3/x + 1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192526 by </B><A HREF=/tutors/aboutme.mpl?userid=kidscomefirst><B>kidscomefirst(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kidscomefirst><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Original problem: x = 3/x + 1/2\r<BR>\n" );
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document.write( "1.  Start my multiplying both sides by x to get this equation in the form of a quadratic.\r<BR>\n" );
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document.write( "x^2 = 3 + 1/2*x\r<BR>\n" );
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document.write( "2.  Then multiply both sides by 2 to eliminate the fraction.  Will make factoring the quadratic easier in the end.\r<BR>\n" );
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document.write( "2x^2 = 6 + x\r<BR>\n" );
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document.write( "3.  Move all of the terms on one side of the equation so that the quadractic equation is set to zero.\r<BR>\n" );
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document.write( "2x^2 - x - 6 = 0\r<BR>\n" );
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document.write( "4.  Use the FOIL method to factor this quadratic equation.\r<BR>\n" );
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document.write( "(2x + 3)(x - 2) = 0\r<BR>\n" );
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document.write( "5.  To find your possible solutions (there are two since this is a quadratic equation), set each factor equal to zero and solve for x.\r<BR>\n" );
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document.write( "2x + 3 = 0 ===> x = -3/2<BR>\n" );
document.write( "x - 2 = 0 ===>  x = 2 </SPAN>\n" );
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