document.write( "Question 261340: solve each in equality give the solution using interval notation \r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "Abs(5-3x)<=7 \n" );
document.write( "
Algebra.Com's Answer #192523 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Abs(5-3x)<=7 \n" ); document.write( "--- \n" ); document.write( "-7 <= 5-3x <= 7 \n" ); document.write( "Subtract 5 along the line: \n" ); document.write( "-12 <= -3x <= 2 \n" ); document.write( "Divide by -3 along the line: \n" ); document.write( "Note: The inequalities reverse. \n" ); document.write( "-2/3 <= x <= 4 \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |