document.write( "Question 261315: Sally places 12 pieces of paper in a basket. Eight are yellow and four are red. Find the probability of the following.
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document.write( "a. if one piece of paper is drawn and is replaced before the second piece of paper is drawn, what is the probability of both pieces of paper being red?
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document.write( "b. Refer to \"a\" If the first piece of paper is not replaced before the second is drawn, what is the probability that both pieces of paper are red? \n" );
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Algebra.Com's Answer #192520 by Theo(13342)![]() ![]() You can put this solution on YOUR website! 12 pieces of paper \n" ); document.write( "eight yellow \n" ); document.write( "4 red.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "question a:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(first red) = 4/12 \n" ); document.write( "p(second red) = 4/12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(red and red) = (4/12) * (4/12) = (16/144) = .11111111...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "question b:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(first red) = 4/12 \n" ); document.write( "p(second red) = 3/11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(red and red) = (4/12) * (3/11) = 12/132 = .0909090909... \n" ); document.write( " \n" ); document.write( " |