document.write( "Question 261317: Ten percent of all people are left handed. If two people are randomly selected, what is the probability of getting one left handed person and one right handed person? \n" ); document.write( "
Algebra.Com's Answer #192519 by Theo(13342)![]() ![]() You can put this solution on YOUR website! probability of a person being left handed is 10% = .1 \n" ); document.write( "probability of a person being right handed is 1 - .1 = .9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(1 left and 1 right) = .1*.9 * 2 = .18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you multiply by 2 because it can happen in 2 ways.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first way is you pick the first person who is left handed and then you pick the second person who is right handed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "second way is you pick the first person who is right handed and then you pick the second person who is left handed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "total possibilities are 0 left and 2 right, 1 left and 1 right, 2 left and 0 right.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(0 left and 2 right) = .9^2 = .81 \n" ); document.write( "p(1 left and 1 right) = .1 * .9 * 2 = .18 \n" ); document.write( "p(2 left and 0 right) = .1^2 = .01\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "total probability is .81 + .18 + .01 = 1 as it should.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your answer is .18.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |