document.write( "Question 32803: Please Help Me Solve This Equation: \"6%2F%28x-1%29+=+4%2F%28x-2%29+-+2%2F%28x%2B1%29\" would the answer be no solution? \n" ); document.write( "
Algebra.Com's Answer #19251 by sarah_adam(201)\"\" \"About 
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6/(x-1) = 4(x+1) - 2(x-2)/ (x-2)(x+1)
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\n" ); document.write( "\n" ); document.write( "6/(x-1) = 4x + 4- 2x - 4/(x-2)(x+1)
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\n" ); document.write( "\n" ); document.write( "6/(x-1) = 4x-2x+4-4/ (x-2)(x+1) Hint (4x-2x = 2x; +4 – 4 = 0)
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\n" ); document.write( "\n" ); document.write( "6/(x-1) = 2x/ (x-2)(x+1)
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\n" ); document.write( "\n" ); document.write( "Now cross multiply:
\n" ); document.write( "6(x-2) (x+1) = 2x(x-1)
\n" ); document.write( "6(x^2 + x – 2x -2) = 2x^2 -2x
\n" ); document.write( "6(x^2 – x -2) =2(x^2 – x)\r
\n" ); document.write( "\n" ); document.write( "Now divide the entire equation with 2
\n" ); document.write( "6(x^2 – x -2)/2 = 2(x^2 – x)/2
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\n" ); document.write( "3(x^2 – x -2) = (x^2 – x)
\n" ); document.write( "3x^2 – 3x – 6 = x^2 – x \r
\n" ); document.write( "\n" ); document.write( "Taking the like terms to same side:
\n" ); document.write( "3x^2 – 3x – 6 – x^2 + x = 0
\n" ); document.write( "3x^2 – x^2 -3x + x - 6 =0
\n" ); document.write( "2x^2 – 2x – 6 = 0
\n" ); document.write( "2(x^2 –x – 3) = 0
\n" ); document.write( "x^2 – x -3 =0\r
\n" ); document.write( "\n" ); document.write( "Solving the equation:
\n" ); document.write( "x = -b +sqrt(b^2+ 4*a*c)/2*a or x = -b - sqrt(b^2 - 4*a*c)/2*a
\n" ); document.write( "where a = coefficient of x^2
\n" ); document.write( " b = coefficient of x
\n" ); document.write( " c = constant
\n" ); document.write( "so here in this equation a = 1 ; b = -1 ; c = -3\r
\n" ); document.write( "\n" ); document.write( "Therfore
\n" ); document.write( "x = 1+ sqrt(1+12)/2 ==> x = 1+ sqrt(13)/2
\n" ); document.write( "or
\n" ); document.write( "x = 1- sqrt(1+12)/2 ==> x = 1-sqrt(13)/2\r
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