document.write( "Question 261306: How do I Graph the function f(x) = x + 2?
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Algebra.Com's Answer #192502 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=1%2Ax%2B2\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-9
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\n" ); document.write( " \"y=1%2A%28-9%29%2B2\"
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\n" ); document.write( " \"y=-9%2B2\" Multiply
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\n" ); document.write( " \"y=-7\" Add
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\n" ); document.write( " So here's one point (-9,-7)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-8
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\n" ); document.write( " \"y=1%2A%28-8%29%2B2\"
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\n" ); document.write( " \"y=-8%2B2\" Multiply
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\n" ); document.write( " \"y=-6\" Add
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\n" ); document.write( " So here's another point (-8,-6). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=1%2Ax%2B2\" through the points (-9,-7) and (-8,-6)
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\n" ); document.write( " So from the graph we can see that the slope is \"1%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 1 units to get to the next point) the y-intercept is (0,\"2\")and the x-intercept is (\"-2\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=2\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"2\").
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\n" ); document.write( " So we have one point (0,\"2\")
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\n" ); document.write( " Now since the slope is \"1%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"2\"), we can go up 1 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=1%2Ax%2B2\"
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\n" ); document.write( " So this is the graph of \"y=1%2Ax%2B2\" through the points (0,2) and (1,3)
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