document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261291>Question 261291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Don is twice as old as Irene; Ed is 16 years older than Irene. The sum of all three of their ages is 60 years. Find the age of each person. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192495 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Don is twice as old as Irene; Ed is 16 years older than Irene. The sum of all three of their ages is 60 years. Find the age of each person.\r<BR>\n" );
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document.write( "D Don, I Irene, E Ed\r<BR>\n" );
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document.write( "D=2I<BR>\n" );
document.write( "E=I+16<BR>\n" );
document.write( "D+I+E=60\r<BR>\n" );
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document.write( "2I + I + I + 16 = 60<BR>\n" );
document.write( "4I + 16 = 60<BR>\n" );
document.write( "4I = 44<BR>\n" );
document.write( "I = 11 which is Irene's age\r<BR>\n" );
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document.write( "so if Irene is 11, then Don is 22 and Ed is 27<BR>\n" );
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