document.write( "Question 261265: Find three consecutive integers such that the sum of the first integer and twice the second integer is 542 more than the third integer. \n" ); document.write( "
Algebra.Com's Answer #192479 by Stitch(470)\"\" \"About 
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The equation: \"+X+%2B+2%2A%28X%2B1%29+=+%28X+%2B+2%29+%2B+542\"
\n" ); document.write( "Simplify the equation
\n" ); document.write( "\"X+%2B+2X+%2B+2+=+X+%2B+544\"
\n" ); document.write( "Subtract 2 from both sides
\n" ); document.write( "\"X+%2B+2X+=+X+%2B+542\"
\n" ); document.write( "Subtract X from both sides
\n" ); document.write( "\"2X+=+542\"
\n" ); document.write( "Divide both sides by 2
\n" ); document.write( "\"highlight%28X+=+271%29\"
\n" ); document.write( "So the numbers are; 271, 272 & 273\r
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\n" ); document.write( "\n" ); document.write( "Check the answer
\n" ); document.write( "-----------------
\n" ); document.write( "\"271+%2B+2%2A272+=+273+%2B+542\" Simplify
\n" ); document.write( "\"highlight%28815+=+815%29\"
\n" ); document.write( "
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