document.write( "Question 261051: Pam is half as old as her brother Bill. Four years ago Bill was six times older than Pam. How old is each sibling now? \n" ); document.write( "
Algebra.Com's Answer #192412 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! (There is an error in another tutor's solution which caused his/her answer to be incorrect. The following is the same as the other solution up to the point of the error.) \n" ); document.write( "Let x = Bill's age now. \n" ); document.write( "Since Pam is half as old as Bill \n" ); document.write( " \n" ); document.write( "Four years ago their ages would be four less than they are now: \n" ); document.write( "x-4 = Bill's age four years ago \n" ); document.write( " \n" ); document.write( "Now that we have expressions for their ages now and four years ago, we can write an equation using the fact that four years ago Bill was six times as old as Pam: \n" ); document.write( " \n" ); document.write( "Using the Distributive Property on the right side we get: \n" ); document.write( " \n" ); document.write( "This simplifies to: \n" ); document.write( " \n" ); document.write( "Now we can solve for x. Subtract x from each side: \n" ); document.write( " \n" ); document.write( "Add 24 to each side: \n" ); document.write( " \n" ); document.write( "Divide both sides by 2: \n" ); document.write( " \n" ); document.write( "Since x is Bill's age now, Bill is ten years old. And since Pam's age now is |