document.write( "Question 261190: state the domain of the given function
\n" ); document.write( "f(x)=sqrt x+2
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Algebra.Com's Answer #192407 by jsmallt9(3758) $\"\"$ $\"About$

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$\"f%28x%29+=+sqrt%28x%2B2%29\"$
\n" ); document.write( "The domain of the function is the set of allowable values for x. There are several reasons for disallowing values for x:

Denominators must not be zero!!
Radicands (the expression in an radical) of even-numbered roots must never be negative (for Real-valued functions).
Arguments to logarithms must never be zero or negative. (IOW, they must be positive.)
Other undefined expressions like $\"tan%28pi%2F2%29\"$

\n" ); document.write( "The only one of these your function has is an even-numbered root. (Square roots are 2nd roots.) So the only thing we have to avoid is a negative value for the radicand. Put another way, our domain must ensure that the radicand, x+2, is equal to zero or positive. In Math terms, the domain is the solution to:
\n" ); document.write( " $\"x+%2B+2+%3E=+0\"$
\n" ); document.write( "Solve this and you have your domain. \n" ); document.write( "

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