document.write( "Question 261066: I need help setting this up.\r
\n" ); document.write( "\n" ); document.write( "Peanuts cost $3 per pound, almonds $4 per pound, and cashews $8 per pound. An event planner wishes to purchase 140 pounds of mixed nuts for $6. per pound, in which there are twice as many peanuts as almond. Can you advise the event planner as to how many of each kind of nut should be in the mixture?
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Algebra.Com's Answer #192392 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let the quantity of peanuts to be mixed =x
\n" ); document.write( "Almonds will be 2x
\n" ); document.write( "Let the cashew nuts mixed be y\r
\n" ); document.write( "\n" ); document.write( "3x+4*2x+8y=140*6=840
\n" ); document.write( "11x+8y=840 ---------1
\n" ); document.write( "3x+y= 140------------2\r
\n" ); document.write( "\n" ); document.write( "Multiply eq2 by 8 and subtract from 1\r
\n" ); document.write( "\n" ); document.write( "24x+8y=1120\r
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\n" ); document.write( "\n" ); document.write( "11x+8y=840
\n" ); document.write( "24x+8y=1120\r
\n" ); document.write( "\n" ); document.write( "-13x= -280
\n" ); document.write( "X=280/13
\n" ); document.write( "=21.54 = peanuts\r
\n" ); document.write( "\n" ); document.write( "2x= 43.08 =almonds\r
\n" ); document.write( "\n" ); document.write( "Y=75.38 = cashew nuts\r
\n" ); document.write( "\n" ); document.write( "M Ananth------------- mananth@hotmail.com\r
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