document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261058>Question 261058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of the complement of an angle is 24 more that one fourth the measure of the supplement of the angle. find the measure of the angle.\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192390 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192390\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the angle be x<BR>\n" );
document.write( "The compliment of the angle is 90-x\r<BR>\n" );
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document.write( "The supplement of the angle is 180-x<BR>\n" );
document.write( "One fourth the measure = ¼(180-x)\r<BR>\n" );
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document.write( "90-x= ¼(180-x) + 24\r<BR>\n" );
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document.write( "90-x-24 = ¼(180-x)\r<BR>\n" );
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document.write( "4(90-x-24)= 180-x<BR>\n" );
document.write( "360-4x-96 = 180-x<BR>\n" );
document.write( "360-96-180=4x-x<BR>\n" );
document.write( "84=3x<BR>\n" );
document.write( "X=28.deg\r<BR>\n" );
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document.write( "M Ananth---- mananth@hotmail.com<BR>\n" );
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