document.write( "Question 261131: Please help me solve this problem: Two cyclists, 30 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist? \n" ); document.write( "
Algebra.Com's Answer #192385 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Two cyclists, 30 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?\r
\n" ); document.write( "\n" ); document.write( "The time they travel to meet is the same since they start at the same time. = 2\r
\n" ); document.write( "\n" ); document.write( "Let speed of one be x
\n" ); document.write( "The speed of the other will be 2x\r
\n" ); document.write( "\n" ); document.write( "The total distance traveled by both the sisters = 30 miles.\r
\n" ); document.write( "\n" ); document.write( "Distance travel by one sister = r * t = 2x
\n" ); document.write( "Distance traveled by other sister = 2*2x=4x\r
\n" ); document.write( "\n" ); document.write( "2x+4x=30
\n" ); document.write( "6x=30
\n" ); document.write( "X=5\r
\n" ); document.write( "\n" ); document.write( "The speeds are 5 and 10 mph\r
\n" ); document.write( "\n" ); document.write( "M Ananth ----------- mananth@hotmail.com
\n" ); document.write( "
\n" ); document.write( "
\n" );