document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261148>Question 261148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jessica and Lauren live on a straight road that runs east to west.  Jessica lives 1 mile west of Lauren.  One morning at 9:00 am, they both start running east.  If Jessica runs 4.5 mph and Lauren runs 3.75 mph, at what time will Jessica catch up to Lauren? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192381 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192381\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let both meet t hours after 9am.<BR>\n" );
document.write( "Distance travelled by Jessica in t hours = 4.5t<BR>\n" );
document.write( "Distance travelled by Lauren in t hours  = 3.75t<BR>\n" );
document.write( "The difference is 4.5t-3.75t = 1 mile<BR>\n" );
document.write( "                  0.75t = 1<BR>\n" );
document.write( "                  t = 1/0.75 hours<BR>\n" );
document.write( "                  t = 1 1/3 hours<BR>\n" );
document.write( "                  t = 1h 20m     </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );