document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261142>Question 261142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.\r<BR>\n" );
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document.write( "If three times the smaller of two consecutive integers is added to four times the larger, the result is 137. Find the smaller integer.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192374 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192374\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two consecutive integers be x and x+1<BR>\n" );
document.write( "Given, 3x+4(x+1) = 137<BR>\n" );
document.write( "       3x+4x+4 = 137<BR>\n" );
document.write( "       7x=137-4<BR>\n" );
document.write( "       x = 133/7<BR>\n" );
document.write( "       x = 19   </SPAN>\n" );
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