document.write( "Question 261100: In a triangle ABC, angle B is 3 times angle A and angle C is 18 less than 6 times angle A. find the size of the angles. The size of angle A is? The size of angle B is? The size of angle C is? \n" ); document.write( "
Algebra.Com's Answer #192362 by jojo14344(1513)\"\" \"About 
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\n" ); document.write( "We know that angles in a triangle equal 180 deg.\r
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\n" ); document.write( "\n" ); document.write( "Then it follows, \"A%2BB%2BC=180%5Eo\", Working Eqn.\r
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\n" ); document.write( "\n" ); document.write( "Let us see the conditions:
\n" ); document.write( "Angle B is 3 times angle A: \"B=3A\", condt'n 1\r
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\n" ); document.write( "\n" ); document.write( "Angle C is 18 less than 6 imes angle A: \"C=6A-18\", condt'n 2\r
\n" ); document.write( "\n" ); document.write( "Substitute the conditions in our Working Eqn:
\n" ); document.write( "\"A%2Bred%283A%29%2Bred%286A-18%29=180%5Eo\"
\n" ); document.write( "\"10A=180%2B18=198\" ---> \"cross%2810%29A%2Fcross%2810%29=cross%28198%2919.8%2Fcross%2810%29\"
\n" ); document.write( "\"red%28A=19.8%5Eo%29\", Answer\r
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\n" ); document.write( "\n" ); document.write( "Let's check by substituting in the condt'ns.
\n" ); document.write( "Condt'n 1: \"B=3%2819.8%29=59.4%5Eo\"
\n" ); document.write( "Condt'n 2: \"C=6%2819.8%29-18=-118.8-18=100.8%5Eo\"\r
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\n" ); document.write( "\n" ); document.write( "Then via Working Eqn:
\n" ); document.write( "\"A%2BB%2BC=180%5Eo\"
\n" ); document.write( "\"19.8%2B59.4%2B100.8=180%5Eo\"
\n" ); document.write( "\"180%5Eo=180%5Eo\"\r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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