document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261113>Question 261113</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The length of a rectangle is four times its width.<BR>\n" );
document.write( "If the perimeter of the rectangle is 60yd , find its area.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192361 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is four times its width.<BR>\n" );
document.write( "If the perimeter of the rectangle is 60yd , find its area\r<BR>\n" );
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document.write( "Let the width be x\r<BR>\n" );
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document.write( "four times width =4x\r<BR>\n" );
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document.write( "60= 2*(l+b)<BR>\n" );
document.write( "60= 2*(4x+x)<BR>\n" );
document.write( "60= 10x<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "Length= 4x= 4*6=24\r<BR>\n" );
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document.write( "Area of rectangle = L*W<BR>\n" );
document.write( "24*6= 144 sq. yards\r<BR>\n" );
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document.write( " M Ananth______ mananth@hotmail.com\r<BR>\n" );
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